JAMB - Mathematics (2001 - No. 2)
Simplify \((\sqrt[3]{64a^{3}})^{-1}\)
4a
1/8a
8a
1/4a
Explanation
\((\sqrt[3]{64a^{3}})^{-1} = (\sqrt[3]{(4a)^{3}})^{-1}\)
= \((4a)^{-1} \)
= \(\frac{1}{4a}\)
Comments (0)
\((\sqrt[3]{64a^{3}})^{-1} = (\sqrt[3]{(4a)^{3}})^{-1}\)
= \((4a)^{-1} \)
= \(\frac{1}{4a}\)
