JAMB - Mathematics (2000 - No. 37)
A function f(x) passes through the origin and its first derivative is 3x + 2. What is f(x)?
y = \(\frac{3x^2}{2}\) + 2x
y = (3x2)/2 + x
y = 3x2 + (x/2)
y = 3x2 +2x
Explanation
Hints:
1. Integrate the given first derivative of f(x) at the boundaries, (0,0)
Then solve accordingly to get f(x) = y = \(\frac{3x^2}{2}\) + 2x
1. Integrate the given first derivative of f(x) at the boundaries, (0,0)
Then solve accordingly to get f(x) = y = \(\frac{3x^2}{2}\) + 2x
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