JAMB - Mathematics (1999 - No. 37)
The diagram above is the graph of y = x\(^2\), the shaded area is
64 square units
128/3 square units
64/3 square units
32 square units
Explanation
\(\int_0 ^4 x^2 dx = \left[\frac{1}{3}x^2+C\right]_0 ^4\)
=\(\frac{1}{3}\times 4^3 - \frac{1}{3}\times 0^3\)
=\(\frac{64}{3}-0\)
=\(\frac{64}{3}\)sq units
=\(\frac{1}{3}\times 4^3 - \frac{1}{3}\times 0^3\)
=\(\frac{64}{3}-0\)
=\(\frac{64}{3}\)sq units
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