JAMB - Mathematics (1999 - No. 27)

What is the derivative of t2 sin (3t - 5) with respect to t?
6t cos (3t - 5)
2t sin (3t - 5) - 3t2 cos (3t - 5)
2t sin (3t - 5) + 3t2 cos (3t - 5)
2t sin (3t - 5) + t2 cos 3t

Explanation

t2 sin (3t - 5) = 2t sin ( 3t - 5) + t2 x 3 cos (3t - 5) = 2t sin (3t - 5) + 3t2 cos (3t - 5).

Detailed answer below was provided by Ifechuks, a female prospective student of Okopoly.

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