JAMB - Mathematics (1998 - No. 11)
Make \(\frac{a}{x}\) the subject of formula \(\frac{x + a}{x - a}\) = m
\(\frac{m - 1}{m + 1}\)
\(\frac{m + 1}{1 - m}\)
\(\frac{m - 1}{1 + m}\)
\(\frac{m + 1}{m - 1}\)
Explanation
\(\frac{x + a}{x - a}\) = m
x + a = mx - ma
a + ma = mx - x
a(m + 1) = x(m - 1)
\(\frac{a}{x}\) = \(\frac{m - 1}{m + 1}\)
x + a = mx - ma
a + ma = mx - x
a(m + 1) = x(m - 1)
\(\frac{a}{x}\) = \(\frac{m - 1}{m + 1}\)
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