JAMB - Mathematics (1997 - No. 34)
Integrate \(\frac{1}{x}\) + cos x with respect to x
-\(\frac{1}{x^2}\) + sin x + k
x + sin x - k
x - sin x + k
-\(\frac{1}{x^2}\) - sin x + k
Explanation
\(\int \frac{1}{x} + \cos x = ln x - \sin x + k\)
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