JAMB - Mathematics (1997 - No. 14)
Find the value of k if \(\frac{5 + 2r}{(r + 1)(r - 2)}\) expressed in partial fraction is \(\frac{k}{r - 2}\) + \(\frac{L}{r + 1}\) where K and L are constants
3
2
1
-1
Explanation
5 + 2r = k(r + 1) + L(r - 2)
but r - 2 = 0 and r = 2
9 = 3k
k = 3
but r - 2 = 0 and r = 2
9 = 3k
k = 3
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