JAMB - Mathematics (1995 - No. 30)
For what value of x is the tangent to the curve y = x\(^2\) - 4x + 3 parallel to the x-axis?
3
2
1
6
Explanation
At the point where the tangent is parallel to the x- axis, the slope of the curve = 0.
Given: \(y = x^{2} - 4x + 3\)
\(\frac{\mathrm d y}{\mathrm d x} = 2x - 4\)
\(2x - 4 = 0 \implies 2x = 4 \)
\(x = 2\)
When x = 2, the tangent of the curve is parallel to the x- axis.
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