JAMB - Mathematics (1993 - No. 7)

If 2log3 y + log3 x2 = 4, then y is
4 - log3
\(\frac{4}{log_3 x}\)
\(\frac{4}{x}\)
\(\pm\) \(\frac{9}{x}\)

Explanation

2log3y + log3x2 = 4

log3y2 + log3x2 = 4

∴ log3 (x2y2) = log381(correct all to base 4)

x2y2 = 81

∴ xy = \(\pm\)9

∴ y = \(\pm\)\(\frac{9}{x}\)

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