JAMB - Mathematics (1993 - No. 47)
In the diagram, QPS = SPR, PR = 9cm. PQ = 4cm and QS = 3cm, find SR.
6\(\frac{3}{4}\)cm
3\(\frac{3}{8}\)cm
4\(\frac{3}{8}\)cm
2\(\frac{3}{8}\)cm
Explanation
Using angle bisector theorem: line PS bisects angle QPR
QS/QP = SR/PR
3/4 = SR/9
4SR = 27
SR = \(\frac{27}{4}\)
= 6\(\frac{3}{4}\)cm
QS/QP = SR/PR
3/4 = SR/9
4SR = 27
SR = \(\frac{27}{4}\)
= 6\(\frac{3}{4}\)cm
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