JAMB - Mathematics (1993 - No. 44)
In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96o, find the value of ORQ.
84o
48o
45o
42o
Explanation
OQ = OR = radii
< ROQ = 180 - 96 = 84º
\(\bigtriangleup\)OQR = Isosceles
R = Q
R + Q + 84 = 180(angle in a \(\bigtriangleup\))
2R = 96 since R = Q
R = 48º
ORQ = 48º
< ROQ = 180 - 96 = 84º
\(\bigtriangleup\)OQR = Isosceles
R = Q
R + Q + 84 = 180(angle in a \(\bigtriangleup\))
2R = 96 since R = Q
R = 48º
ORQ = 48º
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