JAMB - Mathematics (1993 - No. 43)

In the diagram, PQRS is a circle with O as centre and PQ||RT. If RTS = 32°. Find PSQ

32^o

45^o

58^o

90^o

< PSO = \(\frac{1}{2}\) < SOQ = \(\frac{1}{2}\)(180) = 90°

< RTS = < PQS = 32° (Alternative angle)

< PSQ = 90 - < PSQ = 90° - 32°

= 58°