JAMB - Mathematics (1992 - No. 9)
If U = (1, 2, 3, 6, 7, 8, 9, 10) is the universal set. E = (10, 4, 6, 8, 10) and F = {x: 1x\(^{2}\) = 2\(^{6}, x is odd}. Find (E ∩ F)', where ' means the complement of a set.
(0)
U
(8)
\(\phi\)
Explanation
U = (1, 2, 3, 6, 7, 8, 9, 10)
E = (10, 4, 6, 8, 10)
F = (x : x\(^2\) = 2\(^6\), x is odd)
∴ F = \(\phi\) Since x\(^2\) = 2\(^6\) = 64
x = \(\pm 8\) which is even
∴ E ∩ F = \(\phi\) Since there are no common elements
E = (10, 4, 6, 8, 10)
F = (x : x\(^2\) = 2\(^6\), x is odd)
∴ F = \(\phi\) Since x\(^2\) = 2\(^6\) = 64
x = \(\pm 8\) which is even
∴ E ∩ F = \(\phi\) Since there are no common elements
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