JAMB - Mathematics (1992 - No. 4)

What is the value of x satisfying the equation \(\frac{4^{2x}}{4^{3x}}\) = 2?
-2
-\(\frac{1}{2}\)
\(\frac{1}{2}\)
2

Explanation

\(\frac{4^{2x}}{4^{3x}}\) = 2

42x - 3x = 2

4-x = 2

(22)-x

= 21

Equating coefficients: -2x = 1

x = -\(\frac{1}{2}\)

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