JAMB - Mathematics (1992 - No. 26)

X is a point due east of point Y on a coast: Z is another point on the coast but 6√3km due south of y.

If the distance XZ is 12Km. Calculate the bearing of Z from X

240^o

210^o

150^o

60^o

Using sinØ = \(\frac{6√3}{12}\) → \(\frac{√3}{2}\)

sinØ = \(\frac{√3}{2}\) or 60°

The bearing of Z from X = [270 - 60]° → 210°