Let the amounts invested at 4% and 5% respectively be x and y.

\(\therefore x + y = 280 ... (i)\)

Interest on x = \(\frac{x \times 4 \times 1}{100} = 0.04x\)

Interest on y = \(\frac{y \times 5 \times 1}{100} = 0.05y\)

\(\therefore 0.04x + 0.05y = 12.80\)

\(\implies 4x + 5y = 1280 ... (ii)\)

From (i), \(x = 280 - y\).

Put into (ii), \(4(280 - y) + 5y = 1280\)

\(1120 - 4y + 5y = 1280\)

\(1120 + y = 1280 \implies y = 1280 - 1120 = N160\)

\(\therefore\) N160 was invested at the rate of 5% per annum.