JAMB - Mathematics (1988 - No. 18)

Four interior angles of a pentagon are 90o - xo, 90o + xo, 110o - 2xo, 110o + 2xo. Find the fifth interior angle
110o
120o
130o
140o

Explanation

Let the fifth interior angle be y: sum of interior angle of a pentagon

= (2 x 5 - 4) x 90o

= 6 x 90o

= 540o

(90 - x) + (90 + x) + (110 - 2x) + (110 + 2x) + y = 540o

400o + y = 540o

y = 540 - 400o

y = 140o

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