JAMB - Mathematics (1988 - No. 16)
\(\begin{array}{c|c} Scores(x) & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency(f) & 7 & 11 & 6 & 7 & 7 & 5 & 3\end{array}\)
In the distribution above, the mode and median respectively are
In the distribution above, the mode and median respectively are
1,3
1, 2
3, 3
0, 2
Explanation
From the distribution, Mode = 1 and
Median = \(\frac{2 + 2}{2}\)
= 2
= 1, 2
Median = \(\frac{2 + 2}{2}\)
= 2
= 1, 2
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