JAMB - Mathematics (1987 - No. 26)

Find the eleventh term of the progression 4, 8, 16.....
213
212
211
210

Explanation

a = 4, r = \(\frac{4}{2}\)

\(\frac{8}{4}\) = 2

n = 11

Tn = arn - 1

T11 = 4(2)11 - 1

4(2)10 = 212

since 4 = 22

= 212

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