JAMB - Mathematics (1986 - No. 45)

In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35o, TPQ = 20o and PQR is a straight line.Calculate TSR

20^o

55^o

75^o

140^o

Explanation

Given \(\bigtriangleup\) isosceles PQ = QT, SRQ = 35o

TPQ = 20o

PQR = is a straight line

Since PQ = QT, angle P = angle T = 20o

Angle PQR = 180o - (20 + 20) = 140o

TQR = 180o - 140o = 40o < on a straight line

QSR = 180o - (40 + 35)o = 105o

TSR = 180o - 105o

= 75o

JAMB - Mathematics (1986 - No. 45)

Explanation

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