log\(_2\) 4 + log\(_2\) 7 - log\(_2\) n = 1

= log\(_2\) (4 x 7) - log\(_2\) n = 1

\(\therefore\) log\(_2\) 28 - log\(_2\) n = 1

= \(\frac{28}{n} = 2^1\)

\(\frac{28}{n}\) = 2

2n = 28

∴ n = 14