JAMB - Mathematics (1985 - No. 7)
John gives one-third of his money to Janet who has N105.00. He then finds that his money is reduced to one-fourth of what Janet now has. Find how much money john has at first
N45.00
N48.00
N52.00
N60.00
N52.00
Explanation
Let x be John's money, Janet already had N105, \(\frac{1}{3}\) of x was given to Janet
Janet now has \(\frac{1}{3}\)x + 105 = \(\frac{x + 315}{3}\)
John's money left = \(\frac{2}{3}\)x = \(\frac{1}{4} \times\frac{ x + 315}{3}\)
cross multiplying
24x = 3x + 945
∴ x = 45
Janet now has \(\frac{1}{3}\)x + 105 = \(\frac{x + 315}{3}\)
John's money left = \(\frac{2}{3}\)x = \(\frac{1}{4} \times\frac{ x + 315}{3}\)
cross multiplying
24x = 3x + 945
∴ x = 45
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