JAMB - Mathematics (1985 - No. 43)

In the figure POQ is the diameter of the circle PQR. If PSR = 145o, find xo

25^o

35^o

45^o

125^o

55^o

Explanation

< PRQ = \(\frac{1}{2}\) < POQ = 90o

< PSR + < PQR = 180o

< PQR = 180o - 145o = 35o

\(\bigtriangleup\)PQR is a right angled triangle

x = 90 - < PQR

= 90o - 35o

= 55o

JAMB - Mathematics (1985 - No. 43)

Explanation

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