JAMB - Mathematics (1985 - No. 36)
PRSQ is a trapezium of area 14cm2 in which PQ||RS. If PQ = 4cm and SR = 3cm, Find the area of SQR in cm2
7.0
6.0
5.2
5.0
Explanation
Area of trapezium = 14cm2
Area of trapezium = \(\frac{1}{2}\)(a + b)h
14 = \(\frac{1}{2}\)(4 + 3)h
14 = \(\frac{7}{2}\)h
h = \(\frac{14 \times 2}{7}\)
= 4
Area of SQR = \(\frac{1}{2}\)(3 x 4)
= \(\frac{12}{2}\)
= 6.0
Area of trapezium = \(\frac{1}{2}\)(a + b)h
14 = \(\frac{1}{2}\)(4 + 3)h
14 = \(\frac{7}{2}\)h
h = \(\frac{14 \times 2}{7}\)
= 4
Area of SQR = \(\frac{1}{2}\)(3 x 4)
= \(\frac{12}{2}\)
= 6.0
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