JAMB - Mathematics (1985 - No. 22)
Solve the simultaneous equations 2x - 3y + 10, 10x - 6y = - 5
x = 2\(\frac{1}{2}\), y = 5
x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
x = 2\(\frac{1}{4}\), y = 3\(\frac{1}{2}\)
x = 2\(\frac{1}{3}\), y = 3\(\frac{1}{2}\)
x = 2\(\frac{1}{3}\), y = 2\(\frac{1}{2}\)
Explanation
2x - 3y = - 10; 10x - 6y = -5
2x - 3y = -10 x 2
10x - 6y = -5
4x - 6y = -20 .......(i)
10x - 6y = -5.......(ii)
eqn(ii) - eqn(1)
6x = 15
x = \(\frac{15}{6}\)
= \(\frac{5}{2}\)
x = 2\(\frac{1}{2}\)
Sub. for x in equ.(ii) 10(\(\frac{5}{2}\)) - 6y = -5
6y = 25 + 5 → 30
y = \(\frac{30}{6}\)
y = 5
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