JAMB - Mathematics (1984 - No. 40)

In the figure, QRS is a line, PSQ = 35o, SPR = 30o and O is the centre of the circle. Find OQP.

35^o

30^o

130^o

25^o

65^o

< PSQ = 35o, < SPR = 30o

O is the centre of the circle, PRQ = 65o

< OQP = 90 - 65

= 25o