JAMB - Mathematics (1984 - No. 14)
p varies directly as the square of q and inversely as r. If p = 36, when q = 3, when r = 4, find p when q = 5 and r = 2.
72
100
90
200
125
Explanation
P \(\alpha\) \(\frac{q^2}{r}\)
P = \(\frac{kq^2}{r}\)
k = \(\frac{pr}{q^2}\)
= \(\frac{36 x 4}{(3)^2}\)
p = \(\frac{16q^2}{r}\)
= \(\frac{16 \times 25}{2}\)
= 200
P = \(\frac{kq^2}{r}\)
k = \(\frac{pr}{q^2}\)
= \(\frac{36 x 4}{(3)^2}\)
p = \(\frac{16q^2}{r}\)
= \(\frac{16 \times 25}{2}\)
= 200
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