JAMB - Mathematics (1982 - No. 44)

In the fiqure where PQRTU is a circle, ISTI = IRSI and angle TSR = 52^o. Find the angle marked m

128^o

52^o

104^o

64^o

116^o

Explanation

< STR = \(\frac{180 - 52}{2}\) = \(\frac{128}{2}\) = 64^o

< PTR = 180 - < STR(angle on a straight line)

= 180 - 64 = 116^o

< PQR + < PTR = 180(Supplementary)

< PQR + 118 = 180

< PQR = 180 - 118

= 64

M = 180 - < PQR

= 180 - < PQR = 180 - 64

= 116^o

JAMB - Mathematics (1982 - No. 44)

Explanation

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