JAMB - Mathematics (1979 - No. 35)

What is log\(_7{(49^a)}\) - log\(_{10}^{(0.01)}\)?

\(\frac{49^a}{100}\)

\(\frac{a}{2}\) + 2

7^2a + 2

2a + 2

\(\frac{2a}{2}\)

log7(49a) - log10(0.01) = log7(72)a - log10100

log772a - log101 - log10 102

= 2a - 2

= 2a + a