JAMB - Mathematics (1979 - No. 31)

Simplify \(\frac{1 - x^2}{x - x^2}\), where x \(\neq\) 0
\(\frac{1}{x}\)
\(\frac{1 - x}{x}\)
\(\frac{1 + x}{x}\)
\(\frac{1}{x - 1}\)
\(\frac{-x - 1}{1}\)

Explanation

\(\frac{1 - x^2}{x - x^2}\), where x = \(\neq\) 0

\(\frac{1^2 - x^2}{x - x^2}\)

= \(\frac{(1 + x)(1 - x)}{x(1 - x)}\)

= \(\frac{1 + x}{x}\)

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