JAMB - Mathematics (1978 - No. 39)
If x4 - kx3 + 10x2 + lx - 3 is divisible by (x - 1), and if when it is divided by (x + 2) the remainder is 27, find the constants k and l
k = -7, 1 = -15
k = -15, 1 = -7
k = \(\frac{15}{3}\) , 1 = -7
k = \(\frac{7}{3}\) , 1 = -17
Explanation
If k = -7 is put as l = -15, the equation x4 - kx3 + 10x2 + lx - 3 becomes x4 - (7x3) + 10x2 + (15)-3 = x4 + 7x3 + 10x2 - 15x - 3
This equation is divisible by (x - 1) and (x + 2) with the remainder as 27
k = -7, l = -15
This equation is divisible by (x - 1) and (x + 2) with the remainder as 27
k = -7, l = -15
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