JAMB - Chemistry (2025 - No. 56)

C\(_2\)H\(_5\)OH + CH\(_3\)COOH ⇌ CH\(_3\)COOC\(_2\)H\(_5\) + H\(_2\)O

The reaction above is

condensation
fermentation
esterification
hydrolysis

Explanation

The reaction provided shows ethanol (\(\text{C}_{2}\text{H}_{5}\text{OH}\), an alcohol) reacting with ethanoic acid (\(\text{CH}_{3}\text{COOH}\), a carboxylic acid) to produce ethyl ethanoate (\(\text{CH}_{3}\text{COOC}_{2}\text{H}_{5}\), an ester) and water (\(\text{H}_{2}\text{O}\)). The formation of an ester and water from an alcohol and a carboxylic acid is defined as an esterification reaction. This is also a type of condensation reaction, where two molecules combine to form a larger one, eliminating a small molecule (water) in the process.

A. condensation: While esterification is a type of condensation reaction, "esterification" is the specific name for the reaction forming an ester.

B. fermentation: Fermentation is the process of breaking down organic molecules, such as glucose into ethanol and carbon dioxide, in the absence of oxygen, usually with microorganisms. It is not the process shown in the reaction.

D. hydrolysis: Hydrolysis is the reverse reaction, where an ester breaks down into a carboxylic acid and an alcohol by reacting with water.

The correct answer is option C - Esterification

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