Given:

Number of moles, n = 0.5 mole

Mass of acid, m = 44 g

Molar mass of acid, M = ?

Recall that Number of moles, n = \(\frac{mass}{Molecular mass}\)

n = \(\frac{m}{M}\)

M = \(\frac{m}{n}\)

M = \(\frac{44}{0.5}\)

M = 88

:. The molecular mass of the alkanoic acid is 88 - option B