On ionization, Cu\(^{2+}\) + 2e\(^-\) → Cu

2 x 96,500 C liberated 64g Cu

( 2.5 x t) C will liberate 4.5g Cu (Recall that Q = I x t )

By simple proportion, we will have

\(\frac{193,000}{2.5t}\) = \(\frac{64}{4.5}\)

2.5t x 64 = 193,000 x 4.5

160 t = 868,500

t = \(\frac{868,500}{160}\)

t = 5,428.125 seconds

t = 5,428 sec

The correct answer is option C