JAMB - Chemistry (2024 - No. 84)
If 11.0g of a gas occupies 5.6 dm\(^3\) at s.t.p., calculate its vapour density (1 mole of a gas occupies 22.4 dm\(^3\)).
22
44
66
88
Explanation
If 11.0g occupies 5.6 dm\(^3\)
x will occupy 22.4 dm\(^3\)
x = \(\frac{11\times 22.4}{5.6}\)
x = 44g
But Molecular mass = 2 x Vapour density
44 = 2 x Vapour density
Vapour density = \(\frac{44}{2}\) = 22
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