JAMB - Chemistry (2024 - No. 38)

When Sulphur(IV)oxide is passed into solution of acidified tetraoxomanganate(VII), the colour changes from 
blue to green
pink to yellow
purple to colourless
Orange to green

Explanation

When sulphur dioxide (SO\(_2\) gas is passed through an acidified potassium permanganate (KMnO\(_4\)) solution, the solution changes from purple to colourless. This is because of a redox reaction, where KMnO\(_4\) acts as an oxidizing agent and SO\(_2\) acts as a reducing agent.

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