JAMB - Chemistry (2024 - No. 2)
The number of molecules of helium gas contained in 11.5g of the gas is
1.73 x 10\(^{23}\)
1.73 x 10\(^{22}\)
1.73 x 10\(^{24}\)
1.73 x 10\(^{21}\)
Explanation
To find the number of molecules, we'll use the formula:
Number of moles = \(\frac{Number of molecules}{Avogadro number}\)
But We were only given the mass of Helium = 11.5g , knowing the atomic mass or molar mass of He = 4 g/mol
Number of moles = \(\frac{mass}{molar mass}\) = \(\frac{11.5}{4}\) = 2.875 moles
Number of molecules = Number of moles x Avogadro number
= 2.875 x 6.02 x 10\(^{23}\)
= 17.3075 x 10\(^{23}\)
= 1.73 x 10\(^{24}\)
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