JAMB - Chemistry (2024 - No. 112)

The volume occupied by 1 mole of an ideal gas at a temperature of 13\(^0\)C and a pressure of 1.58 atm is

[ R = 0.082 atm dm\(^3\) K\(^{-1}\)mol\(^{-1}\) ]

14.84 dm\(^3\)

14.84 cm\(^3\)

0.64 dm\(^3\)

0.64 cm\(^3\)

According to the Ideal gas equation, PV = nRT

Given: P = 1.58 atm, V = ?, n = 1 mole, R = 0.082, T= 13 + 273K = 286K

Substituting all the given parameters,

V = \(\frac{nRT}{P}\)

V = \(\frac{1\times0.082\times286}{1.58}\)

V = 14.84 dm\(^3\)