JAMB - Chemistry (2022 - No. 23)
2H\(_2\) + O\(_2\) → 2H\(_2\)O
From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm\(^3\) of hydroden and 75cm\(^3\) of oxygen are involved
85cm\(^3\)
50cm\(^3\)
125cm\(^3\)
55cm\(^3\)
Explanation
Since 2 mol H\(_2\) reacted with 1 mol of O\(_2\)
: 50cm\(^3\) of hydrogen reacted with 25cm\(^3\) of oxygen
Remainder oxygen = Supplied amount - Reacted amount → 75cm\(^3\) - 25cm\(^3\)
= 50cm\(^3\)
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