Given:

T\(_1\) = 273K ; V\(_1\) =  X  ; P\(_1\) = Y 

T\(_2\) = ? ; V\(_2\) =  2X   P\(_2\) = 2Y  ( Remember we were told the volume and pressure were doubled )

We also represented V\(_1\) and P\(_1\) to be X and Y respective,y since we were not given.

Using the formula:  \(\frac{{P_1}{V_1}}{T_1}\) = \(\frac{{P_2}{V_2}}{T_2}\)

 T\(_2\) = \(\frac{{P_2}{V_2}{T_1}}{{P_1}{V_1}}\) 

  = \(\frac{{2Y}\times{2X}\times{273}}{{Y}\times{X}}\)  

  = 2 x 2 x 273

  = 1092 K