JAMB - Chemistry (2018 - No. 1)

A given amount of gas occupies 10.0dm\(^3\) at 4 atm and 273°C. The number of moles of the gas present is?

[Molar volume of gas at s.t.p = 22.4 dm\(^3\)]

0.89 mol

1.90 mol

3.80 mol

5.70 mol

Given:

P = 4 atm , V = 10 dm\(^3\) , n = ? R = 0.082 (constant) T = 273 + 273 = 546K

Using the ideal gas law, PV = nRT

n = \(\frac{PV}{RT}\)

n = \(\frac{{4}\times{10}}{{0.082}\times{546}}\)

n = \(\frac{40}{44.772}\)

n = 0.893 mole