JAMB - Chemistry (2017 - No. 16)
A sample of orange juice is found to have a PH of 3.80. What is the concentration of the hydroxide ion in the juice?
1.6 \(\times\) 10-4
6.3 \(\times\) 10-11
6.3 \(\times\) 10-4
1.6 \(\times\) 10-11
Explanation
PH = - Log[ H+ ]
PH + POH =14
POH = 14 - 3.8
POH = 10.2
POH = - Log[ OH- ]
10.2 = - Log[ OH- ]
10-10.2 = [ OH- ]
[ OH- ] = 6.3 x 10-11
PH + POH =14
POH = 14 - 3.8
POH = 10.2
POH = - Log[ OH- ]
10.2 = - Log[ OH- ]
10-10.2 = [ OH- ]
[ OH- ] = 6.3 x 10-11
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