JAMB - Chemistry (2015 - No. 59)
In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is
4H+ 4e - 2H2
4OH= 4e- + 2H2O + O2
2OH - 2e- = 2OH
2OH- + 2OH = 2H2O + O2
Explanation
40H − 4e → 2H2O + O2is the reaction of sun at the anode in the electrolysis of CuSO4 (g) using platinum particles. Option A,C,D are not formed as a result of the equation