JAMB - Chemistry (2014 - No. 24)
If the change in free energy of a system is -899 Jmol-1 and the entropy change is 10Jmol-1k-1 at 250C, calculate the enthalpy change.
+2081 Jmol-1
-2081 Jmol-1
-649 Jmol-1
+649 Jmol-1
Explanation
∆G = ∆H - T∆S
-899 = ∆H - 2980
∆H = -899 + 2980 = + 2081 Jmol-1
-899 = ∆H - 2980
∆H = -899 + 2980 = + 2081 Jmol-1
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