JAMB - Chemistry (2012 - No. 24)

What number of moles of Cu 2+ will be deposited by 360 coulombs of electricity?
[f = 96500 C mol -1]

5.36 x 10 ^-4 mole

1. 87 x 10 10 ^-3 mole

9. 35 x 10 ^-4 mole

3. 73 x 10 ^-3

Cu\(^{2+}\) + 2e\(^{-}\)\(_{(aq)}\) \(\rightarrow\) Cu\(_{(s)}\)

Liberating 1 mole of Cu

2 x 1F = 2 x 96,500C = 193,000C of electricity is needed

Hence, 193,000C = 1 mole

360C of electricity = \(\frac{360C \times 1 mol}{193,000C}\)

= 0.001865 mol

= 1.87 x 10\(^{-3}\) moles