JAMB - Chemistry (2006 - No. 42)
Na\(_2\)CO\(_3\)(g) + 2HCl(aq) → 2NaCl(aq) + H\(_2\)O(l) + CO\(_2\)(g)
How many moles of sodium trioxocarbonate (IV) are there in a 25 cm\(^3\) solution which required 10cm\(^3\) of 0.05 mol dm\(^3\) hydrochloric acid solution to neutralize it?
How many moles of sodium trioxocarbonate (IV) are there in a 25 cm\(^3\) solution which required 10cm\(^3\) of 0.05 mol dm\(^3\) hydrochloric acid solution to neutralize it?
1.000 mole
0.100 mole
0.010 mole`
0.111 mole
Explanation
\(\frac{C_A V_A}{C_BV_B} = \frac{a}{b}\)
\(\frac{0.05 \times 10}{C_B \times 25} = \frac{2}{1}\)
50C\(_B\) = 0.5
C\(_B\) = \(\frac{0.5}{50} = \frac{1}{100}\)
= 0.01
\(\frac{0.05 \times 10}{C_B \times 25} = \frac{2}{1}\)
50C\(_B\) = 0.5
C\(_B\) = \(\frac{0.5}{50} = \frac{1}{100}\)
= 0.01
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