JAMB - Chemistry (2006 - No. 21)
When 50cm\(^3\) of a saturated solution of sugar of molar mass 342 g at 40\(^o\)C was evaporated to dryness, 34.2g of dry solid was obtained. The solubility of sugar at 40\(^o\)C is
2.0 mol dm-3
3.5 mol dm-3
7.0 mol dm-3
10.0 mol dm-3
Explanation
Given:
Volume of solvent, V = 50cm\(^3\)
Molar mass, M = 342g
Mass of solute, m = 34.2g
Solubility = ?
Solubility = \(\frac{mass}{molar mass}\times\)\(\frac{1000}{Volume of solvent}\)
= \(\frac{34.2}{342}\times\)\(\frac{1000}{50}\)
= 2 moldm\(^{-3}\)
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