JAMB - Chemistry (2003 - No. 44)
A compound contains 40.0% carbon 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180, find the molecular formula.
[H = 1, C = 12, O = 16]
[H = 1, C = 12, O = 16]
CH2O
C3H6O3
C6H12O6
C6H12O3
Explanation
C - 40% ; 40/12 = 3.33
H - 6.7% ; 6.7/1 = 6.7
O - 53.3% ; 53.3/16 = 3.33
C = 3.33/3.33 = 1
H = 6.7/3.33 = 2
O = 3.33/3.33 = 1
CH2O
(CH2O)n = 180
(12 + 2 + 16)~n = 180
30n = 180
n = 6
= C6H12O6
H - 6.7% ; 6.7/1 = 6.7
O - 53.3% ; 53.3/16 = 3.33
C = 3.33/3.33 = 1
H = 6.7/3.33 = 2
O = 3.33/3.33 = 1
CH2O
(CH2O)n = 180
(12 + 2 + 16)~n = 180
30n = 180
n = 6
= C6H12O6
Comments (0)
