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JAMB - Chemistry (2001 - No. 24)

2SO\(_2\)(g) + O\(_2\)(g) ↔ 2SO\(_3\)(g)
ΔH = -189 kJ mol-1
The equilibrium constant for the reaction above is increased by?
decreasing the temperature of the system
decrease the pressure of the system
The addition of a catalyst to the system
Increasing the surface area of the vessel

Explanation

Decrease in temperature favors in Equilibrium Constant[k] for this exothermic reaction. 

The only factor that can affect an equilibrium constant is temperature:

  • Endothermic reactions

    Increasing the temperature increases the equilibrium constant, and decreasing the temperature decreases it.

  • Exothermic reactions

    Increasing the temperature decreases the equilibrium constant, and decreasing the temperature increases it. - Option A

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