JAMB - Chemistry (2001 - No. 21)
What current in amperes will deposit 2.7g of aluminium in 2 hours?
[Al = 27, F = 96 500 C mol-1]
[Al = 27, F = 96 500 C mol-1]
32
8
4
16
Explanation
Al\(^{3+}\) + 3e\(^-\) → Al
3 x 96500 → 27g
I = 3600 x 2 → 27
I = (2.7/27) x ((3 x 96500)/(3600 x 2))
= 4.025 ≈ 4
3 x 96500 → 27g
I = 3600 x 2 → 27
I = (2.7/27) x ((3 x 96500)/(3600 x 2))
= 4.025 ≈ 4
Comments (0)
